X=-16y^2+32y-20

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Solution for X=-16y^2+32y-20 equation: 



X=-16X^2+32X-20

We move all terms to the left:

X-(-16X^2+32X-20)=0

We get rid of parentheses

16X^2-32X+X+20=0

We add all the numbers together, and all the variables

16X^2-31X+20=0

a = 16; b = -31; c = +20;
Δ = b2-4ac
Δ = -312-4·16·20
Δ = -319
Delta is less than zero, so there is no solution for the equation

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